What is the integral from 2 to 3 of 1/(sqrt(x-2)) ?

The integral from 2 to 3 of 1/(sqrt(x-2)) is 2

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integral from 2 to 3 of 1/(sqrt(x-2))

\int_{2}^{3} \frac{1}{x - 2} d x

2

Solution steps

\int_{2}^{3} \frac{1}{x - 2} d x

Apply u-substitution

: \int_{0}^{1} 2 d u

= \int_{0}^{1} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{1}

Compute the boundaries:

2

= 2

\int_{0}^{2} π (x^{3})^{2} d x

\int_{0}^{π} sin (θ) cos^{2} (θ) d θ

\int_{0}^{π} sin (5 x + π) d x

\int_{1}^{2} 1 + x^{2} d x

\int_{- 2}^{2} 2 x d x

What is the integral from 2 to 3 of 1/(sqrt(x-2)) ?
The integral from 2 to 3 of 1/(sqrt(x-2)) is 2