What is the integral from 0 to 6 of 2x^2+3x-1 ?

The integral from 0 to 6 of 2x^2+3x-1 is 192

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integral from 0 to 6 of 2x^2+3x-1

\int_{0}^{6} 2 x^{2} + 3 x - 1 d x

192

Solution steps

\int_{0}^{6} 2 x^{2} + 3 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{6} 2 x^{2} d x + \int_{0}^{6} 3 x d x - \int_{0}^{6} 1 d x

\int_{0}^{6} 2 x^{2} d x = 144

\int_{0}^{6} 3 x d x = 54

\int_{0}^{6} 1 d x = 6

= 144 + 54 - 6

Simplify

= 192

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What is the integral from 0 to 6 of 2x^2+3x-1 ?
The integral from 0 to 6 of 2x^2+3x-1 is 192