What is the integral from 0 to 2 of-x ?

The integral from 0 to 2 of-x is -2

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integral from 0 to 2 of-x

\int_{0}^{2} - x d x

- 2

Solution steps

\int_{0}^{2} - x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2}

= - [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= - 2

\int_{3}^{- 3} (6 r + 5)^{2} d r

\int_{1}^{\infty} \frac{1}{x ^{a}} d x

\int_{- 1}^{2} 2 x^{2} - 2 x - 4 d x

\int_{0}^{2} 2^{x} - 1 - \frac{3 x}{2} d x

\int_{0}^{2} \frac{1}{x ^{2} + 4 x + 3} d x