What is the integral from 0 to pi/2 of-cos(x) ?

The integral from 0 to pi/2 of-cos(x) is -1

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integral from 0 to pi/2 of-cos(x)

\int_{0}^{\frac{π}{2}} - cos (x) d x

- 1

Solution steps

\int_{0}^{\frac{π}{2}} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= - 1

\int_{0}^{4} (x^{3} - x^{2} + 1) d x

\int_{- 5}^{4} - x^{2} - 3 x d x

\int_{1}^{2} (3 x^{2} - 2 x + 1) d x

\int_{0}^{1} x cos (πn x) d x

\int_{0}^{\frac{1}{2}} ln (1 - x^{2}) d x

What is the integral from 0 to pi/2 of-cos(x) ?
The integral from 0 to pi/2 of-cos(x) is -1