What is the integral from-1 to 1 of 3 ?

The integral from-1 to 1 of 3 is 6

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integral from-1 to 1 of 3

\int_{- 1}^{1} 3 d x

6

Solution steps

\int_{- 1}^{1} 3 d x

Integral of a constant:

\int a d x = a x

= [3 x]_{- 1}^{1}

Compute the boundaries:

6

= 6

\int_{0}^{2} 3^{2 x} d x

\int_{0}^{1} e^{t^{2}} d t

\int_{2}^{6} 2 x d x

\int_{0}^{\frac{π}{6}} t sin (2 t) d t

\int_{0}^{1} \frac{y}{( 2 y ^{2} + 1 ) ^{3}} d y