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Popular >

integral from-1 to 1 of |2-4x|

Solution

\int_{- 1}^{1} ∣ 2 - 4 x ∣ d x

Solution

5

Solution steps

\int_{- 1}^{1} ∣ 2 - 4 x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{\frac{1}{2}} 2 - 4 x d x + \int_{\frac{1}{2}}^{1} - 2 + 4 x d x

\int_{- 1}^{\frac{1}{2}} 2 - 4 x d x = \frac{9}{2}

\int_{\frac{1}{2}}^{1} - 2 + 4 x d x = \frac{1}{2}

= \frac{9}{2} + \frac{1}{2}

Simplify

\frac{9}{2} + \frac{1}{2} : 5

= 5

Graph

Popular Examples

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\int_{0}^{2} (4 - y^{2}) d y

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\int_{0}^{11} ∣ 9 - x ∣ d x

integral from 0 to 1 of y^2(1-y^{3/2})

\int_{0}^{1} y^{2} (1 - y^{\frac{3}{2}}) d y

integral from 0 to 2 of sqrt(x^2-2x+1)

\int_{0}^{2} x^{2} - 2 x + 1 d x

integral from 0 to pi/4 of 3sec(θ)tan(θ)

\int_{0}^{\frac{π}{4}} 3 sec (θ) tan (θ) d θ

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of |2-4x| ?
The integral from-1 to 1 of |2-4x| is 5