What is the integral from 2 to 5 of (x^2+5x) ?

The integral from 2 to 5 of (x^2+5x) is 183/2

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integral from 2 to 5 of (x^2+5x)

\int_{2}^{5} (x^{2} + 5 x) d x

\frac{183}{2}

Decimal

91.5

Solution steps

\int_{2}^{5} x^{2} + 5 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} x^{2} d x + \int_{2}^{5} 5 x d x

\int_{2}^{5} x^{2} d x = 39

\int_{2}^{5} 5 x d x = \frac{105}{2}

= 39 + \frac{105}{2}

Simplify

39 + \frac{105}{2} : \frac{183}{2}

= \frac{183}{2}

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What is the integral from 2 to 5 of (x^2+5x) ?
The integral from 2 to 5 of (x^2+5x) is 183/2