What is the integral from 0 to 2 of (6x^2y-2x) ?

The integral from 0 to 2 of (6x^2y-2x) is -4x+12x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (6x^2y-2x)

\int_{0}^{2} (6 x^{2} y - 2 x) d y

- 4 x + 12 x^{2}

Solution steps

\int_{0}^{2} 6 x^{2} y - 2 x d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} 2 x d y + \int_{0}^{2} 6 x^{2} y d y

\int_{0}^{2} 2 x d y = 4 x

\int_{0}^{2} 6 x^{2} y d y = 12 x^{2}

= - 4 x + 12 x^{2}

\int_{0}^{\frac{π}{2}} sin (2 x) sin (x) d x

\int_{0}^{1} 4^{2 x} d x

\int_{e}^{4} \frac{1}{x ln ( x )} d x

\int_{2}^{4} 5 x d x

\int_{- 1}^{2} (3 x - ∣ x ∣) d x

What is the integral from 0 to 2 of (6x^2y-2x) ?
The integral from 0 to 2 of (6x^2y-2x) is -4x+12x^2