What is the integral from 0 to 4 of 5(1-e^y) ?

The integral from 0 to 4 of 5(1-e^y) is 5(-e^4+5)

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integral from 0 to 4 of 5(1-e^y)

\int_{0}^{4} 5 (1 - e^{y}) d y

5 (- e^{4} + 5)

Decimal

- 247.99075 \dots

Solution steps

\int_{0}^{4} 5 (1 - e^{y}) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{4} 1 - e^{y} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 5 (\int_{0}^{4} 1 d y - \int_{0}^{4} e^{y} d y)

\int_{0}^{4} 1 d y = 4

\int_{0}^{4} e^{y} d y = e^{4} - 1

= 5 (4 - (e^{4} - 1))

Simplify

= 5 (- e^{4} + 5)

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What is the integral from 0 to 4 of 5(1-e^y) ?
The integral from 0 to 4 of 5(1-e^y) is 5(-e^4+5)