What is the integral from 0 to 1 of 3y^2 ?

The integral from 0 to 1 of 3y^2 is 1

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integral from 0 to 1 of 3y^2

\int_{0}^{1} 3 y^{2} d y

1

Solution steps

\int_{0}^{1} 3 y^{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{0}^{1}

= 3 [\frac{y ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= 3 \cdot \frac{1}{3}

Simplify

= 1

\int_{0}^{1} \frac{1}{2 x - x ^{2}} d x

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What is the integral from 0 to 1 of 3y^2 ?
The integral from 0 to 1 of 3y^2 is 1