What is the integral from pi/2 to pi of (sin(x))/x ?

The integral from pi/2 to pi of (sin(x))/x is \Si(pi)-\Si(pi/2)

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integral from pi/2 to pi of (sin(x))/x

\int_{\frac{π}{2}}^{π} \frac{sin ( x )}{x} d x

Si (π) - Si (\frac{π}{2})

Solution steps

\int_{\frac{π}{2}}^{π} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{\frac{π}{2}}^{π}

Compute the boundaries:

Si (π) - Si (\frac{π}{2})

= Si (π) - Si (\frac{π}{2})

\int_{0}^{π} \frac{1}{2} sin (x) d x

\int_{2}^{3} \frac{2 x}{( x ^{2} + 2 ) ^{2}} d x

\int_{b}^{a} \frac{1}{x} d x

\int_{0}^{l n (2)} 6 e^{3 x} d x

\int_{0}^{L} x^{2} d x

What is the integral from pi/2 to pi of (sin(x))/x ?
The integral from pi/2 to pi of (sin(x))/x is \Si(pi)-\Si(pi/2)