What is the integral from 0 to 3 of 1/(sqrt(x+1)) ?

The integral from 0 to 3 of 1/(sqrt(x+1)) is 2

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integral from 0 to 3 of 1/(sqrt(x+1))

\int_{0}^{3} \frac{1}{x + 1} d x

2

Solution steps

\int_{0}^{3} \frac{1}{x + 1} d x

Apply u-substitution

: \int_{1}^{2} 2 d u

= \int_{1}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{1}^{2}

Compute the boundaries:

2

= 2

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What is the integral from 0 to 3 of 1/(sqrt(x+1)) ?
The integral from 0 to 3 of 1/(sqrt(x+1)) is 2