What is the integral from 0 to 4 of (x^2)/4 ?

The integral from 0 to 4 of (x^2)/4 is 16/3

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integral from 0 to 4 of (x^2)/4

\int_{0}^{4} \frac{x ^{2}}{4} d x

\frac{16}{3}

Decimal

5.33333 \dots

Solution steps

\int_{0}^{4} \frac{x ^{2}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= \frac{1}{4} [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= \frac{1}{4} \cdot \frac{64}{3}

Simplify

= \frac{16}{3}

\int_{- 1}^{1} (x^{2} + 2 x + 1) d x

\int_{0}^{\frac{π}{2}} 4 cos^{4} (x) d x

\int_{2}^{4} x - 2 d x

\int_{\frac{1}{2}}^{2} \frac{1}{x} d x

\int_{1}^{x^{4}} sec (t) d t

What is the integral from 0 to 4 of (x^2)/4 ?
The integral from 0 to 4 of (x^2)/4 is 16/3