What is the sum from n=1 to infinity of 1/((n+2)^2) ?

The sum from n=1 to infinity of 1/((n+2)^2) is converges

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sum from n=1 to infinity of 1/((n+2)^2)

n = 1 \sum \infty \frac{1}{( n + 2 ) ^{2}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{( n + 2 ) ^{2}}

Apply Series Comparison Test:

converges

= converges

y = \frac{3}{16 - x}, at x = 0

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\int_{0}^{\frac{1}{2}} 1 d x

\int (3 x^{2} + 1)^{3} d x

What is the sum from n=1 to infinity of 1/((n+2)^2) ?
The sum from n=1 to infinity of 1/((n+2)^2) is converges