What is the integral from-pi/4 to 0 of 1/(cos^2(x)) ?

The integral from-pi/4 to 0 of 1/(cos^2(x)) is 1

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integral from-pi/4 to 0 of 1/(cos^2(x))

\int_{- \frac{π}{4}}^{0} \frac{1}{cos ^{2} ( x )} d x

1

Solution steps

\int_{- \frac{π}{4}}^{0} \frac{1}{cos ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{cos ^{2} ( x )} d x = tan (x)

= [tan (x)]_{- \frac{π}{4}}^{0}

Compute the boundaries:

1

= 1

\int_{0}^{y} \frac{1}{2 y} d y

\int_{0}^{2} 3 x^{2} + 1 d x

\int_{s i n (x)}^{c o s (x)} x^{2} d x

\int_{0}^{\frac{π}{2}} x cos (x) d x

\int_{1}^{3} \frac{ln ( x )}{x ^{2}} d x

What is the integral from-pi/4 to 0 of 1/(cos^2(x)) ?
The integral from-pi/4 to 0 of 1/(cos^2(x)) is 1