What is the integral from 0 to 3 of (32x^3+4x) ?

The integral from 0 to 3 of (32x^3+4x) is 666

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integral from 0 to 3 of (32x^3+4x)

\int_{0}^{3} (32 x^{3} + 4 x) d x

666

Solution steps

\int_{0}^{3} 32 x^{3} + 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 32 x^{3} d x + \int_{0}^{3} 4 x d x

\int_{0}^{3} 32 x^{3} d x = 648

\int_{0}^{3} 4 x d x = 18

= 648 + 18

Simplify

= 666

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What is the integral from 0 to 3 of (32x^3+4x) ?
The integral from 0 to 3 of (32x^3+4x) is 666