What is the integral from 0 to 5 of 1/x ?

The integral from 0 to 5 of 1/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5 of 1/x

\int_{0}^{5} \frac{1}{x} d x

diverges

Solution steps

\int_{0}^{5} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{0}^{5}

Compute the boundaries:

diverges

= diverges

\int_{\frac{π}{4}}^{\frac{3 π}{4}} cot (x) d x

\int_{π}^{2 π} 5 sin (2 x) d x

\int_{0}^{4} 3 x d x

\int_{- 1}^{1} ∣ x ∣ - x^{2} d x

\int_{0}^{1} x 7 x^{2} + 9 d x

What is the integral from 0 to 5 of 1/x ?
The integral from 0 to 5 of 1/x is diverges