What is the integral from 0 to 1 of x^3x^2 ?

The integral from 0 to 1 of x^3x^2 is 1/6

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integral from 0 to 1 of x^3x^2

\int_{0}^{1} x^{3} x^{2} d x

\frac{1}{6}

Decimal

0.16666 \dots

Solution steps

\int_{0}^{1} x^{3} x^{2} d x

Simplify

x^{3} x^{2} : x^{5}

= \int_{0}^{1} x^{5} d x

Apply the Power Rule

: [\frac{x ^{6}}{6}]_{0}^{1}

= [\frac{x ^{6}}{6}]_{0}^{1}

Compute the boundaries:

\frac{1}{6}

= \frac{1}{6}

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What is the integral from 0 to 1 of x^3x^2 ?
The integral from 0 to 1 of x^3x^2 is 1/6