What is the limit as x approaches 0+of 4/(5x^{1/3)} ?

The limit as x approaches 0+of 4/(5x^{1/3)} is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 4/(5x^{1/3)}

x \to 0 + lim (\frac{4}{5 x ^{\frac{1}{3}}})

\infty

Solution steps

x \to 0 + lim (\frac{4}{5 x ^{\frac{1}{3}}})

For

x

approaching

0

from the right

, x > 0 \Rightarrow 5 x^{\frac{1}{3}} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d y}{d x} = \frac{y + x ^{2} + y ^{2}}{x}

\frac{d}{d x} ((2 x^{3} - 5) (x^{2} - 5 ln (x)))

\frac{d}{d x} (\frac{x}{csc ( x )})

f^{^{'}} (x) = \frac{e ^{x}}{x}

\frac{\partial}{\partial y} (3 z e^{x y})

What is the limit as x approaches 0+of 4/(5x^{1/3)} ?
The limit as x approaches 0+of 4/(5x^{1/3)} is infinity