What is the integral from 0 to 1 of sin(x)cos(x) ?

The integral from 0 to 1 of sin(x)cos(x) is (sin^2(1))/2

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integral from 0 to 1 of sin(x)cos(x)

\int_{0}^{1} sin (x) cos (x) d x

\frac{sin ^{2} ( 1 )}{2}

Decimal

0.35403 \dots

Solution steps

\int_{0}^{1} sin (x) cos (x) d x

Apply u-substitution

: \int_{0}^{s i n (1)} u d u

= \int_{0}^{s i n (1)} u d u

Apply the Power Rule

: [\frac{u ^{2}}{2}]_{0}^{s i n (1)}

= [\frac{u ^{2}}{2}]_{0}^{s i n (1)}

Compute the boundaries:

\frac{sin ^{2} ( 1 )}{2}

= \frac{sin ^{2} ( 1 )}{2}

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\int_{1}^{e^{1}} sin (ln (x)) d x

\int_{4}^{7} \frac{1}{x ^{2}} d x

What is the integral from 0 to 1 of sin(x)cos(x) ?
The integral from 0 to 1 of sin(x)cos(x) is (sin^2(1))/2