What is the integral from 0 to 1 of 6xy^2 ?

The integral from 0 to 1 of 6xy^2 is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 6xy^2

\int_{0}^{1} 6 x y^{2} d y

2 x

Solution steps

\int_{0}^{1} 6 x y^{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 x \cdot \int_{0}^{1} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{0}^{1}

= 6 x [\frac{y ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= 6 x \frac{1}{3}

Simplify

= 2 x

\int_{3}^{1} 7 d x

\int_{0}^{1} \frac{x}{1 + x y} d y

\int_{0}^{x} cos (t^{4}) d t

\int_{0}^{1} 3 x e^{x^{2}} d x

\int_{0}^{2} x sin (x^{2}) d x

What is the integral from 0 to 1 of 6xy^2 ?
The integral from 0 to 1 of 6xy^2 is 2x