What is the integral from 9.1 to 9.6 of (12x^2-6x+4) ?

The integral from 9.1 to 9.6 of (12x^2-6x+4) is 498.60999…

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integral from 9.1 to 9.6 of (12x^2-6x+4)

\int_{9.1}^{9.6} (12 x^{2} - 6 x + 4) d x

498.60999 \dots

Solution steps

\int_{9.1}^{9.6} 12 x^{2} - 6 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{9.1}^{9.6} 12 x^{2} d x - \int_{9.1}^{9.6} 6 x d x + \int_{9.1}^{9.6} 4 d x

\int_{9.1}^{9.6} 12 x^{2} d x = 524.65999 \dots

\int_{9.1}^{9.6} 6 x d x = 28.05

\int_{9.1}^{9.6} 4 d x = 2

= 524.65999 \dots - 28.05 + 2

Simplify

= 498.60999 \dots

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What is the integral from 9.1 to 9.6 of (12x^2-6x+4) ?
The integral from 9.1 to 9.6 of (12x^2-6x+4) is 498.60999…