What is the integral from 0 to 9 of (sqrt(x)) ?

The integral from 0 to 9 of (sqrt(x)) is 18

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integral from 0 to 9 of (sqrt(x))

\int_{0}^{9} (x) d x

18

Solution steps

\int_{0}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{9}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{9}

Compute the boundaries:

18

= 18

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What is the integral from 0 to 9 of (sqrt(x)) ?
The integral from 0 to 9 of (sqrt(x)) is 18