What is the integral from 0 to 8 of 1000x+250 ?

The integral from 0 to 8 of 1000x+250 is 34000

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 8 of 1000x+250

\int_{0}^{8} 1000 x + 250 d x

34000

Solution steps

\int_{0}^{8} 1000 x + 250 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{8} 1000 x d x + \int_{0}^{8} 250 d x

\int_{0}^{8} 1000 x d x = 32000

\int_{0}^{8} 250 d x = 2000

= 32000 + 2000

Simplify

= 34000

\int_{4}^{3} sin (x) d x

\int_{0}^{1} \frac{x}{( x ^{2} + 1 )} d x

\int_{1}^{2} \frac{2}{x ^{2}} - 3 x^{2} - 1 d x

\int_{0}^{π} cos (x) sin^{4} (x) d x

\int_{2}^{4} x^{2} - 4 d x

What is the integral from 0 to 8 of 1000x+250 ?
The integral from 0 to 8 of 1000x+250 is 34000