What is the integral from-1 to 0 of-x^2 ?

The integral from-1 to 0 of-x^2 is -1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 0 of-x^2

\int_{- 1}^{0} - x^{2} d x

- \frac{1}{3}

Decimal

- 0.33333 \dots

Solution steps

\int_{- 1}^{0} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 1}^{0} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{0}

= - [\frac{x ^{3}}{3}]_{- 1}^{0}

Compute the boundaries:

\frac{1}{3}

= - \frac{1}{3}

\int_{1}^{e} x d x

\int_{- 2}^{2} (- 2 x^{2} + 8) d x

\int_{0}^{1} (1 + 2 x^{2}) d x

\int_{0}^{1} \frac{x}{1 + x ^{3}} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} (cos (x) - 2) d x

What is the integral from-1 to 0 of-x^2 ?
The integral from-1 to 0 of-x^2 is -1/3