What is the integral from 0 to 2pi of 2cos(x) ?

The integral from 0 to 2pi of 2cos(x) is 0

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integral from 0 to 2pi of 2cos(x)

\int_{0}^{2 π} 2 cos (x) d x

0

Solution steps

\int_{0}^{2 π} 2 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{2 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 2 [sin (x)]_{0}^{2 π}

Compute the boundaries:

0

= 2 \cdot 0

Simplify

= 0

\int_{2}^{1} 2 x d x

\int_{0}^{s i n (x)} 1 - x^{2} d x

\int_{2}^{\infty} x d x

\int_{1}^{4} (2 x) d x

\int_{0}^{π} sin (x) - x^{2} + π x d x

What is the integral from 0 to 2pi of 2cos(x) ?
The integral from 0 to 2pi of 2cos(x) is 0