What is the integral from 0 to 3 of 1/(x^3) ?

The integral from 0 to 3 of 1/(x^3) is diverges

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integral from 0 to 3 of 1/(x^3)

\int_{0}^{3} \frac{1}{x ^{3}} d x

diverges

Solution steps

\int_{0}^{3} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{0}^{3}

= [- \frac{1}{2 x ^{2}}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

\int_{- π}^{π} 2 x d x

\int_{0}^{θ} \frac{2 x ^{2}}{θ ^{2}} d x

\int_{0}^{4} π (2 x^{2})^{2} d x

\int_{- \frac{π}{4}}^{\frac{π}{4}} sec (x) d x

\int_{0}^{x} y x^{2} - y^{2} d y

What is the integral from 0 to 3 of 1/(x^3) ?
The integral from 0 to 3 of 1/(x^3) is diverges