What is (\partial)/(\partial z)(x^2-xyz) ?

The answer to (\partial)/(\partial z)(x^2-xyz) is -xy

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(\partial)/(\partial z)(x^2-xyz)

\frac{\partial}{\partial z} (x^{2} - x yz)

- x y

Solution steps

\frac{\partial}{\partial z} (x^{2} - x yz)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x^{2}) - \frac{\partial}{\partial z} (x yz)

\frac{\partial}{\partial z} (x^{2}) = 0

\frac{\partial}{\partial z} (x yz) = x y

= 0 - x y

Simplify

= - x y

y^{^{''}} - y^{^{'}} - 42 y = 0

\frac{d}{d x} ((3 x + 2)^{x})

y^{^{''}} + y^{^{'}} + 4 y = 0

6 x sin (x)

\frac{\partial}{\partial y} (x^{\frac{x}{y}} cos (\frac{x}{y}))

What is (\partial)/(\partial z)(x^2-xyz) ?
The answer to (\partial)/(\partial z)(x^2-xyz) is -xy