What is the integral from x to x^2 of t^4 ?

The integral from x to x^2 of t^4 is (x^{10}-x^5)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from x to x^2 of t^4

\int_{x}^{x^{2}} t^{4} d t

\frac{x ^{10} - x ^{5}}{5}

Solution steps

\int_{x}^{x^{2}} t^{4} d t

Apply the Power Rule

: [\frac{t ^{5}}{5}]_{x}^{x^{2}}

= [\frac{t ^{5}}{5}]_{x}^{x^{2}}

Compute the boundaries:

\frac{x ^{10}}{5} - \frac{x ^{5}}{5}

= \frac{x ^{10}}{5} - \frac{x ^{5}}{5}

Simplify

= \frac{x ^{10} - x ^{5}}{5}

\int_{0.2}^{2.2} x e^{x} d x

\int_{0}^{1} 2 x + 3 d x

\int_{0}^{1} (4 + 3 x^{2}) d x

\int_{- 1}^{1} x^{2} + 2 x + 1 d x

\int_{- 8}^{- 1} 1 - 3 x d x

What is the integral from x to x^2 of t^4 ?
The integral from x to x^2 of t^4 is (x^{10}-x^5)/5