What is the integral from-infinity to 0 of ye^{4y} ?

The integral from-infinity to 0 of ye^{4y} is -1/16

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integral from-infinity to 0 of ye^{4y}

\int_{- \infty}^{0} y e^{4 y} d y

- \frac{1}{16}

Decimal

- 0.0625

Solution steps

\int_{- \infty}^{0} y e^{4 y} d y

Compute the indefinite integral:

\int y e^{4 y} d y = \frac{1}{16} (e^{4 y} \cdot 4 y - e^{4 y}) + C

Compute the boundaries:

\int_{- \infty}^{0} y e^{4 y} d y = - \frac{1}{16} - 0

= - \frac{1}{16} - 0

Simplify

= - \frac{1}{16}

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What is the integral from-infinity to 0 of ye^{4y} ?
The integral from-infinity to 0 of ye^{4y} is -1/16