What is the integral from 0 to 1 of x^{12}+12^x ?

The integral from 0 to 1 of x^{12}+12^x is 1/13+(11)/(ln(12))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of x^{12}+12^x

\int_{0}^{1} x^{12} + 1 2^{x} d x

\frac{1}{13} + \frac{11}{ln ( 12 )}

Decimal

4.50364 \dots

Solution steps

\int_{0}^{1} x^{12} + 1 2^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{12} d x + \int_{0}^{1} 1 2^{x} d x

\int_{0}^{1} x^{12} d x = \frac{1}{13}

\int_{0}^{1} 1 2^{x} d x = \frac{11}{ln ( 12 )}

= \frac{1}{13} + \frac{11}{ln ( 12 )}

\int_{\frac{1}{2}}^{2} (4 - \frac{4}{x ^{2}}) d x

\int_{3}^{4} \frac{1}{x ^{2} - 3 x + 2} d x

\int_{2}^{4} (2 x + 1) d x

\int_{- 2}^{0} 9 x^{2} (2 x^{3} + 4)^{2} d x

\int_{0}^{2} x^{3} + x d x

What is the integral from 0 to 1 of x^{12}+12^x ?
The integral from 0 to 1 of x^{12}+12^x is 1/13+(11)/(ln(12))