What is the integral from 0 to 1 of sqrt(y) ?

The integral from 0 to 1 of sqrt(y) is 2/3

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integral from 0 to 1 of sqrt(y)

\int_{0}^{1} y d y

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{0}^{1} y d y

Apply the Power Rule

: [\frac{2}{3} y^{\frac{3}{2}}]_{0}^{1}

= [\frac{2}{3} y^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

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\int_{2}^{6} \frac{1}{4 x + 1} d x

What is the integral from 0 to 1 of sqrt(y) ?
The integral from 0 to 1 of sqrt(y) is 2/3