What is the integral from 0 to infinity of te^{-2t} ?

The integral from 0 to infinity of te^{-2t} is 1/4

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integral from 0 to infinity of te^{-2t}

\int_{0}^{\infty} t e^{- 2 t} d t

\frac{1}{4}

Decimal

0.25

Solution steps

\int_{0}^{\infty} t e^{- 2 t} d t

Compute the indefinite integral:

\int t e^{- 2 t} d t = \frac{1}{4} (- 2 e^{- 2 t} t - e^{- 2 t}) + C

Compute the boundaries:

\int_{0}^{\infty} t e^{- 2 t} d t = 0 - (- \frac{1}{4})

= 0 - (- \frac{1}{4})

Simplify

= \frac{1}{4}

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What is the integral from 0 to infinity of te^{-2t} ?
The integral from 0 to infinity of te^{-2t} is 1/4