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Popular >

integral from 0 to 2 of (1-x)

Solution

\int_{0}^{2} (1 - x) d x

Solution

0

Solution steps

\int_{0}^{2} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 1 d x - \int_{0}^{2} x d x

\int_{0}^{2} 1 d x = 2

\int_{0}^{2} x d x = 2

= 2 - 2

Simplify

= 0

Graph

Popular Examples

integral from 1 to 2 of (t+1/t)^2

\int_{1}^{2} (t + \frac{1}{t})^{2} d t

integral from-2 to 0 of (x^2y-2xy)

\int_{- 2}^{0} (x^{2} y - 2 x y) d y

integral from x to 4-x of (x^2y+1/y)

\int_{x}^{4 - x} (x^{2} y + \frac{1}{y}) d y

integral from-4 to 3 of |x|

\int_{- 4}^{3} ∣ x ∣ d x

integral from 0 to 1 of e^{x+1}

\int_{0}^{1} e^{x + 1} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (1-x) ?
The integral from 0 to 2 of (1-x) is 0