What is the integral from 0 to 1-x of xcos(y) ?

The integral from 0 to 1-x of xcos(y) is xcos(y)(-x+1)

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integral from 0 to 1-x of xcos(y)

\int_{0}^{1 - x} x cos (y) d z

x cos (y) (- x + 1)

Solution steps

\int_{0}^{1 - x} x cos (y) d z

Integral of a constant:

\int a d x = a x

= [cos (y) x z]_{0}^{1 - x}

Compute the boundaries:

x cos (y) (- x + 1)

= x cos (y) (- x + 1)

\int_{1}^{x^{2}} sin (t) d t

\int_{0}^{2} x cos (x) d x

\int_{- 1}^{3} 3 x^{4} d x

\int_{0}^{1} x^{\frac{1}{3}} - x d x

\int_{0}^{2} 15 x^{2} d x

What is the integral from 0 to 1-x of xcos(y) ?
The integral from 0 to 1-x of xcos(y) is xcos(y)(-x+1)