What is (\partial)/(\partial y)(y(e^x-1)) ?

The answer to (\partial)/(\partial y)(y(e^x-1)) is e^x-1

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(\partial)/(\partial y)(y(e^x-1))

\frac{\partial}{\partial y} (y (e^{x} - 1))

e^{x} - 1

Solution steps

\frac{\partial}{\partial y} (y (e^{x} - 1))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (e^{x} - 1) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= (e^{x} - 1) \cdot 1

Simplify

= e^{x} - 1

\int (sec^{2} (x) - 1) d x

x \to - 2 lim (2 x + 9)

\int x sin (- 1 x) d x

\int e^{- y} d y

F (x) = sin (tan (3 x))

What is (\partial)/(\partial y)(y(e^x-1)) ?
The answer to (\partial)/(\partial y)(y(e^x-1)) is e^x-1