What is the integral from-2 to 2 of-x^2 ?

The integral from-2 to 2 of-x^2 is -16/3

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integral from-2 to 2 of-x^2

\int_{- 2}^{2} - x^{2} d x

- \frac{16}{3}

Decimal

- 5.33333 \dots

Solution steps

\int_{- 2}^{2} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- 2}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{2}

= - [\frac{x ^{3}}{3}]_{- 2}^{2}

Compute the boundaries:

\frac{16}{3}

= - \frac{16}{3}

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\int_{0}^{4} \frac{1}{4 - x} d x

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What is the integral from-2 to 2 of-x^2 ?
The integral from-2 to 2 of-x^2 is -16/3