What is the derivative of ln(sqrt(3x+1)) ?

The derivative of ln(sqrt(3x+1)) is 3/(2(3x+1))

What is the first derivative of ln(sqrt(3x+1)) ?

The first derivative of ln(sqrt(3x+1)) is 3/(2(3x+1))

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\frac{d}{d x} (ln (3 x + 1))

\frac{3}{2 ( 3 x + 1 )}

Solution steps

\frac{d}{d x} (ln (3 x + 1))

Apply the chain rule:

\frac{1}{3 x + 1} \frac{d}{d x} (3 x + 1)

= \frac{1}{3 x + 1} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = \frac{3}{2 3 x + 1}

= \frac{1}{3 x + 1} \cdot \frac{3}{2 3 x + 1}

Simplify

\frac{1}{3 x + 1} \cdot \frac{3}{2 3 x + 1} : \frac{3}{2 ( 3 x + 1 )}

= \frac{3}{2 ( 3 x + 1 )}

\frac{d}{d x} (sin^{5} (2 x^{5} - e^{- 2 x}))

y = x^{3} - 3 x^{2} + 1

f (x) = - 7

y^{^{'}} - \frac{1}{x} y = 9

x^{2} + 2, at x = - 1

What is the derivative of ln(sqrt(3x+1)) ?
The derivative of ln(sqrt(3x+1)) is 3/(2(3x+1))
What is the first derivative of ln(sqrt(3x+1)) ?
The first derivative of ln(sqrt(3x+1)) is 3/(2(3x+1))