What is the integral from 0 to 1 of cos(x)+e^2 ?

The integral from 0 to 1 of cos(x)+e^2 is sin(1)+e^2

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integral from 0 to 1 of cos(x)+e^2

\int_{0}^{1} cos (x) + e^{2} d x

sin (1) + e^{2}

Solution steps

\int_{0}^{1} cos (x) + e^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} cos (x) d x + \int_{0}^{1} e^{2} d x

\int_{0}^{1} cos (x) d x = sin (1)

\int_{0}^{1} e^{2} d x = e^{2}

= sin (1) + e^{2}

\int_{0}^{b} e^{- x} d x

\int_{- 2}^{1} x^{2} + 2 x + 1 d x

\int_{- 1}^{2} x + 2 d x

\int_{- 1}^{1} \frac{1}{x ^{2} - 5 x + 6} d x

\int_{2}^{4} \frac{8}{x ^{2}} d x

What is the integral from 0 to 1 of cos(x)+e^2 ?
The integral from 0 to 1 of cos(x)+e^2 is sin(1)+e^2