What is the integral from 2 to 5 of 2000x+1000 ?

The integral from 2 to 5 of 2000x+1000 is 24000

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 5 of 2000x+1000

\int_{2}^{5} 2000 x + 1000 d x

24000

Solution steps

\int_{2}^{5} 2000 x + 1000 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{5} 2000 x d x + \int_{2}^{5} 1000 d x

\int_{2}^{5} 2000 x d x = 21000

\int_{2}^{5} 1000 d x = 3000

= 21000 + 3000

Simplify

= 24000

\int_{- 2}^{5} x^{2} - 3 x - 10 d x

\int_{5}^{10} \frac{2 t}{t ^{2} + 1} d t

\int_{- 2}^{1} \frac{t}{( t ^{2} + 1 ) ^{2}} d t

\int_{0}^{2 π} x^{4} + 4 x^{2} d x

\int_{0}^{20} x d x

What is the integral from 2 to 5 of 2000x+1000 ?
The integral from 2 to 5 of 2000x+1000 is 24000