What is the integral from 1 to infinity of (e^x)/x ?

The integral from 1 to infinity of (e^x)/x is diverges

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integral from 1 to infinity of (e^x)/x

\int_{1}^{\infty} \frac{e ^{x}}{x} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{e ^{x}}{x} d x

Compute the indefinite integral:

\int \frac{e ^{x}}{x} d x = Ei (x) + C

Compute the boundaries:

\int_{1}^{\infty} \frac{e ^{x}}{x} d x =

diverges

= diverges

\int_{0}^{3} (x - 4) d x

\int_{0}^{2} ∣ 2 - x ∣ d x

\int_{0}^{π} \frac{1}{1 + sin ( x )} d x

\int_{- 3}^{2} (2 x^{3} - 4 x) d x

\int_{0}^{2} 4 x - x^{2} d x

What is the integral from 1 to infinity of (e^x)/x ?
The integral from 1 to infinity of (e^x)/x is diverges