What is the integral from 0 to ln(5) of 2e^{2x} ?

The integral from 0 to ln(5) of 2e^{2x} is 24

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integral from 0 to ln(5) of 2e^{2x}

\int_{0}^{l n (5)} 2 e^{2 x} d x

24

Solution steps

\int_{0}^{l n (5)} 2 e^{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{l n (5)} e^{2 x} d x

Apply u-substitution

: \int_{0}^{2 l n (5)} e^{u} \frac{1}{2} d u

= 2 \cdot \int_{0}^{2 l n (5)} e^{u} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int_{0}^{2 l n (5)} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 2 \cdot \frac{1}{2} [e^{u}]_{0}^{2 l n (5)}

Simplify

2 \cdot \frac{1}{2} [e^{u}]_{0}^{2 l n (5)} : [e^{u}]_{0}^{2 l n (5)}

= [e^{u}]_{0}^{2 l n (5)}

Compute the boundaries:

24

= 24

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What is the integral from 0 to ln(5) of 2e^{2x} ?
The integral from 0 to ln(5) of 2e^{2x} is 24