What is the integral from 8 to 9 of 1 ?

The integral from 8 to 9 of 1 is 1

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integral from 8 to 9 of 1

\int_{8}^{9} 1 d t

1

Solution steps

\int_{8}^{9} 1 d t

Integral of a constant:

\int a d x = a x

= [1 \cdot t]_{8}^{9}

Simplify

= [t]_{8}^{9}

Compute the boundaries:

1

= 1

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