What is the integral from-infinity to 0 of e^{ax} ?

The integral from-infinity to 0 of e^{ax} is 1/a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of e^{ax}

\int_{- \infty}^{0} e^{a x} d x

\frac{1}{a}

Solution steps

\int_{- \infty}^{0} e^{a x} d x

Compute the indefinite integral:

\int e^{a x} d x = \frac{1}{a} e^{a x} + C

Compute the boundaries:

\int_{- \infty}^{0} e^{a x} d x = \frac{1}{a} - 0

= \frac{1}{a} - 0

Simplify

= \frac{1}{a}

\int_{0}^{\frac{π}{4}} cos^{2} (θ) d θ

\int_{4}^{8} \frac{1}{x ^{2}} d x

\int_{x}^{1} 2 x sin (x) d x

\int_{0}^{1} 4 r^{2} + 1 r d r

\int_{0}^{x} cos (3 t) d t

What is the integral from-infinity to 0 of e^{ax} ?
The integral from-infinity to 0 of e^{ax} is 1/a