en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 2x-x^2

Solution

\int_{1}^{4} 2 x - x^{2} d x

Solution

- 6

Solution steps

\int_{1}^{4} 2 x - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 2 x d x - \int_{1}^{4} x^{2} d x

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} x^{2} d x = 21

= 15 - 21

Simplify

= - 6

Popular Examples

integral from 0 to 2 of t/(sqrt(5+t^2))

\int_{0}^{2} \frac{t}{5 + t ^{2}} d t

integral from 1 to e of ln(\sqrt[x]{x})

integral from 0 to pi/4 of sin(2x+pi/2)

\int_{0}^{\frac{π}{4}} sin (2 x + \frac{π}{2}) d x

integral from 0 to pi/2 of x^2*cos(x)

\int_{0}^{\frac{π}{2}} x^{2} \cdot cos (x) d x

integral from 0 to 1 of x^2*sqrt(1-x^2)

\int_{0}^{1} x^{2} \cdot 1 - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of 2x-x^2 ?
The integral from 1 to 4 of 2x-x^2 is -6