What is the integral from 0 to 15pi of sin(x) ?

The integral from 0 to 15pi of sin(x) is 2

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integral from 0 to 15pi of sin(x)

\int_{0}^{15 π} sin (x) d x

2

Solution steps

\int_{0}^{15 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{15 π}

Compute the boundaries:

2

= 2

\int_{0}^{3} 5^{2 x} d x

\int_{0}^{1} x \cdot e^{2 x} d x

\int_{- 1}^{3} x^{2} + 2 x d x

\int_{0}^{2} x \cdot \frac{3}{4} x (2 - x) d x

\int_{0}^{3} sin (\frac{nπ x}{3}) d x

What is the integral from 0 to 15pi of sin(x) ?
The integral from 0 to 15pi of sin(x) is 2