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Popular >

integral from-1 to 1 of 1+|x|

Solution

\int_{- 1}^{1} 1 + ∣ x ∣ d x

Solution

3

Solution steps

\int_{- 1}^{1} 1 + ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{0} 1 - x d x + \int_{0}^{1} 1 + x d x

\int_{- 1}^{0} 1 - x d x = \frac{3}{2}

\int_{0}^{1} 1 + x d x = \frac{3}{2}

= \frac{3}{2} + \frac{3}{2}

Simplify

\frac{3}{2} + \frac{3}{2} : 3

= 3

Popular Examples

integral from 0 to 2 of xsqrt(x^2+5)

\int_{0}^{2} x x^{2} + 5 d x

integral from 1/2 to 3 of (x^2-1)/(x^2)

\int_{\frac{1}{2}}^{3} \frac{x ^{2} - 1}{x ^{2}} d x

integral from-9 to 9 of (81-x^2)

\int_{- 9}^{9} (81 - x^{2}) d x

integral from 0 to 1 of arctan(y)

\int_{0}^{1} arctan (y) d y

integral from 0 to 1 of 8x(x^2+1)^3

\int_{0}^{1} 8 x (x^{2} + 1)^{3} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 1+|x| ?
The integral from-1 to 1 of 1+|x| is 3