What is the integral from 1 to 3 of (x+3)^3 ?

The integral from 1 to 3 of (x+3)^3 is 260

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integral from 1 to 3 of (x+3)^3

\int_{1}^{3} (x + 3)^{3} d x

260

Solution steps

\int_{1}^{3} (x + 3)^{3} d x

Apply u-substitution

: \int_{4}^{6} u^{3} d u

= \int_{4}^{6} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{4}^{6}

= [\frac{u ^{4}}{4}]_{4}^{6}

Compute the boundaries:

260

= 260

\int_{- 3}^{0} x + 3 + 9 - x^{2} d x

\int_{2}^{- 1} (2 x + 1)^{2} d x

\int_{0}^{\frac{π}{2}} (cos (2 x)) d x

\int_{1}^{2} t 9 + 16 t^{2} d t

\int_{- 2}^{x} (4 t^{2} - 3 t) d t

What is the integral from 1 to 3 of (x+3)^3 ?
The integral from 1 to 3 of (x+3)^3 is 260