What is the integral from 0 to 1 of x/((x^2+3)^3) ?

The integral from 0 to 1 of x/((x^2+3)^3) is 7/576

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integral from 0 to 1 of x/((x^2+3)^3)

\int_{0}^{1} \frac{x}{( x ^{2} + 3 ) ^{3}} d x

\frac{7}{576}

Solution steps

\int_{0}^{1} \frac{x}{( x ^{2} + 3 ) ^{3}} d x

Apply u-substitution

: \int_{3}^{4} \frac{1}{2 u ^{3}} d u

= \int_{3}^{4} \frac{1}{2 u ^{3}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{3}^{4} \frac{1}{u ^{3}} d u

Apply the Power Rule

: [- \frac{1}{2 u ^{2}}]_{3}^{4}

= \frac{1}{2} [- \frac{1}{2 u ^{2}}]_{3}^{4}

Compute the boundaries:

\frac{7}{288}

= \frac{1}{2} \cdot \frac{7}{288}

Simplify

= \frac{7}{576}

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What is the integral from 0 to 1 of x/((x^2+3)^3) ?
The integral from 0 to 1 of x/((x^2+3)^3) is 7/576