What is the integral from 4.2 to 9.9 of (12x^2-6x+4) ?

The integral from 4.2 to 9.9 of (12x^2-6x+4) is 3366.534

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integral from 4.2 to 9.9 of (12x^2-6x+4)

\int_{4.2}^{9.9} (12 x^{2} - 6 x + 4) d x

3366.534

Solution steps

\int_{4.2}^{9.9} 12 x^{2} - 6 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.2}^{9.9} 12 x^{2} d x - \int_{4.2}^{9.9} 6 x d x + \int_{4.2}^{9.9} 4 d x

\int_{4.2}^{9.9} 12 x^{2} d x = 3584.844

\int_{4.2}^{9.9} 6 x d x = 241.11

\int_{4.2}^{9.9} 4 d x = 22.8

= 3584.844 - 241.11 + 22.8

Simplify

= 3366.534

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What is the integral from 4.2 to 9.9 of (12x^2-6x+4) ?
The integral from 4.2 to 9.9 of (12x^2-6x+4) is 3366.534